Question

Glucose and gluconic acid treated with dilute nitric acid forms saccharic acid. What does this indicate?

Options

• This suggests that all six carbon atoms of glucose are in the form of straight chain.

• Carbonyl group in glucose is aldehydic.

• Presence of primary alcoholic group in glucose.

• Presence of five hydroxyl groups in glucose.

Answer 1

Presence of primary alcoholic group in glucose.

Explanation:

Both give saccharic acid due to the presence of 1° alcoholic group in glucose.