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Question
\[\ce{H2O2 -> 2H^+ + O2 + 2e^-}\]; E0 = −0.68 V.
This equation represents which of the following behaviour of H2O2?
Options
Reducing
Oxidising
Acidic
Catalytic
MCQ
Solution
Reducing
Explanation:
As H2O2 loses electrons, it acts as a reducing agent.
shaalaa.com
Balancing Redox Reactions in Terms of Loss and Gain of Electrons
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