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Question
Half-life of a first order reaction is 30 minutes and initial concentration of reactant is 0.1 M.
What is half-life of the reaction if initial concentration of reactant is doubled?
Options
900 second
3600 second
600 second
1800 second
MCQ
Solution
1800 second
Explanation:
Half-life of a first order reaction is given by formulae `"t"_(1//2) = 0.693/"K"`
Half-life is independent of concentration of reactant.
So, at any value of concentration half-life remains same, i.e.
30 minutes = 30 × 60 seconds = 1800 seconds.
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