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HBr reacts with CHA2=CH−OCHA3 under anhydrous conditions at room temperature to give ______. -

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Question

HBr reacts with \[\ce{CH2 = CH - OCH3}\] under anhydrous conditions at room temperature to give ______.

Options

  • \[\ce{BrCH2 - CH2 - OCH3}\]

  • \[\ce{H3C - CHBr - OCH3}\]

  • \[\ce{CH3CHO and CH3Br}\]

  • \[\ce{BrCH2CHO and CH3OH}\]

MCQ
Fill in the Blanks

Solution

HBr reacts with \[\ce{CH2 = CH - OCH3}\] under anhydrous conditions at room temperature to give \[\underline{\ce{H3C - CHBr - OCH3}}\].

Explanation:

Methyl vinyl ether under anhydrous condition at room temperature undergoes addition reaction.

\[\begin{array}{cc}
\ce{CH2 = CH - OCH3 ->[HBr] CH3 - CH - O - CH3}\\
\phantom{...................}|\\
\phantom{....................}\ce{Br}
\end{array}\]

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