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Question
Henry’s law constant for solubility of methane in benzene is 4.2 × 10-5 mm Hg at a particular constant temperature. At this temperature calculate the solubility of methane at
- 750 mm Hg
- 840 mm Hg.
Solution
`("K"_"H")_"benzene"` = 4.2 × 10-5 mm
Solubility of methane = ?
P = 750 mm Hg P = 840 mm Hg
According to Henrys Law,
P = KH `"X"_"in solution"`
750 mm Hg = 4.2 × 10-5 mm Hg. `"X"_"in solution"`
⇒ `"X"_"in solution" = 750/(4.2 xx 10^-5)`
i. e solubility = 178. 5 × 105
similarly at P = 840 mm Hg
solubility = `840/(4.2 xx 10^-5) = 200 xx 10^-5`
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