Advertisements
Advertisements
Question
How can you determine the atomic mass of an unknown metal if you know its density and the dimension of its unit cell? Explain.
Solution
By knowing the density of an unknown metal and the dimension of its unit cell, the atomic mass of the metal can be determined.
Let ‘a’ be the edge length of a unit cell of a crystal, ‘d’ be the density of the metal, ‘m’ be the mass of one atom of the metal and ‘z’ be the number of atoms in the unit cell.
Now, density of the unit cell = `"Mass of Unit cell"/"Volume of unit cell"`
`=>d = "zm"/a^3` ....(i)
[Since mass of the unit cell = Number of atoms in the unit cell × mass of one atom]
[Volume of the unit cell = (Edge length of the cubic unit cell)3]
From equation (i), we have:
`m = (da^3)/z` .....(ii)
Now, mass of one atom of metal (m) = `("Atomic mass (M)")/("Avogadro's number "(N_A))`
Therefore M = `(d a^3N_A)/z` .....(iii)
If the edge lengths are different (say a, b and c), then equation (ii) becomes:
`M = (d(abc)N_A)/z` .....(IV)
From equations (iii) and (iv), we can determine the atomic mass of the unknown metal.
APPEARS IN
RELATED QUESTIONS
Gold occurs as face centred cube and has a density of 19.30 kg dm-3. Calculate atomic radius of gold (Molar mass of Au = 197)
Distinguish between Hexagonal and monoclinic unit cells
Distinguish between Face-centred and end-centred unit cells.
Explain how much portion of an atom located at (i) corner and (ii) body-centre of a cubic unit cell is part of its neighbouring unit cell.
Calculate the percentage efficiency of packing in case of simple cubic cell.
A face centred cube (FCC) consists of how many atoms? Explain
An element has atomic mass 93 g mol–1 and density 11.5 g cm–3. If the edge length of its unit cell is 300 pm, identify the type of unit cell
Calculate the number of unit cells in 8.1 g of aluminium if it crystallizes in a f.c.c. structure. (Atomic mass of Al = 27 g mol–1)
The density of silver having an atomic mass of 107.8 g mol- 1 is 10.8 g cm-3. If the edge length of cubic unit cell is 4.05 × 10- 8
cm, find the number of silver atoms in the unit cell.
( NA = 6.022 × 1023, 1 Å = 10-8 cm)
What is the total number of atoms per unit cell in a face-centered cubic structure?
An element forms a cubic unit cell with edge length 405 pm. Molar mass of this element is 2.7 × 10−2 kg/mol and its density is given as 2.7 × 103 kg/m3. How many atoms of these elements are present per unit cell?
An element (atomic mass 100 g/mol) having bcc structure has unit cell edge 400 pm. The density of element is (No. of atoms in bcc, Z = 2).
Which of the following metal(s) show(s) hexagonal close-packed structure (hcp) and which show face-centered cubic (fcc) structure?
The percentage of empty space in a body centred cubic arrangement is ______.
The correct set of quantum numbers for 3d subshell is
Percentage of free space in body centred cubic unit cell is
If a represents the edge length of the cubic systems, i.e. simple cubic, body centred cubic and face centered cubic, then the ratio of the radii of the sphere in these system will be:-
An element A (Atomic weight = 100) having bcc structure has a unit cell edge length 400 pm. The number of atoms in 10 g of A is ______ × 1022 unit cells.