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Karnataka Board PUCPUC Science 2nd PUC Class 12

How do you explain the amphoteric behaviour of amino acids? - Chemistry

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Question

How do you explain the amphoteric behaviour of amino acids?

Chemical Equations/Structures
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Solution

In aqueous solution, the carboxyl group of an amino acid can lose a proton and the amino group can accept a proton to give a dipolar ion known as zwitter ion.

\[\begin{array}{cc}
\phantom{.........}\ce{O}\phantom{........................}\ce{O}\phantom{....}\\
\phantom{......}||\phantom{.........................}||\phantom{.}\\
\ce{R - CH - C - O - H <=> R - CH - C - O-}\\
|\phantom{.........................}|\phantom{........}\\
\ce{:NH2}\phantom{..................}\ce{\underset{(Zwitter ion)}{^+NH3}}\phantom{.....}
\end{array}\]

Therefore, in zwitter ionic form, the amino acid can act both as an acid and as a base.

\[\begin{array}{cc}
\phantom{.....}\ce{O}\phantom{.....................}\ce{O}\phantom{......................}\ce{O}\\
\phantom{.....}||\phantom{......................}||\phantom{......................}||\\
\ce{R - CH - C - O- <=>[H+][OH-] R - CH - C - O- <=>[H+][OH-] R - CH - C - OH}\\
|\phantom{......................}|\phantom{.......................}|\phantom{........}\\
\ce{NH2}\phantom{.................}\ce{^+NH3}\phantom{..................}\ce{^+NH3}\phantom{.....}
\end{array}\]

Thus, amino acids show amphoteric behaviour.

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Chapter 14: Biomolecules - Exercises [Page 423]

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NCERT Chemistry [English] Class 12
Chapter 14 Biomolecules
Exercises | Q 16 | Page 423
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