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Question
How does a compiler decide as to which function should be invoked when there are many functions? Give an example.
Answer in Brief
Solution
When you call an overloaded function (when there are many functions with the same name), the compiler determines the most appropriate definition to use by comparing the argument types used to call the function with the parameter types specified in the definitions. The process of selecting the most appropriate overloaded function or operator is called overload resolution.
Example:
#include using namespace std; void print (int i)
{
cout<< “It is integer” <<i<< endl;
}
void print (string c)
{
cout<< “It is string”<< c << endl;
}
int main ()
{
print (10);
print (“Good”);
return 0;
}
Output:
It is integer 10
It is string Good
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