Advertisements
Advertisements
Question
How many kilograms of sugar costing ₹9 per kg must be mixed with 27 kg of sugar costing ₹7 per kg so that there may be a gain of 10% by selling the mixture at ₹9.24 per kg?
Options
36 kg
42 kg
54 kg
63 kg
MCQ
Solution
63 kg
Explanation:
SP of 1 kg of mixture = ₹9.24
Gain= 10%
∴ CP of 1 kg of mixture
= ₹`(100/110xx9.24)=`₹8.40
By the rule of alligation, we have
\[\begin{array}{cc}
₹9\phantom{...........}₹7\\
\setminus \phantom{............}/ \\
\ce{\underset{₹8.40}{Mean Profit}}\\
/\phantom{............} \setminus \\
₹1.40 \phantom{..............}₹0.60
\end{array}\]
₹9\phantom{...........}₹7\\
\setminus \phantom{............}/ \\
\ce{\underset{₹8.40}{Mean Profit}}\\
/\phantom{............} \setminus \\
₹1.40 \phantom{..............}₹0.60
\end{array}\]
∴ Ratio of quantities of 1st and 2nd kind = 14 : 6 = 7 : 3
Let x kg of sugar of 1st be mixed with 27 kg of 2nd kind.
Then, `7:3=x:27`
⇒ `x=((7xx27)/3)`
= 63kg
shaalaa.com
Ratio and Proportion (Entrance Exam)
Is there an error in this question or solution?