Question

How many primary, secondary and tertiary carbon atoms respectively are present in isobutane?

Options

• 3, 0 and 1

• 3, 1 and 0

• 0, 1 and 3

• 1, 0 and 3

Answer 1

3, 0 and 1

Explanation:

\[\begin{array}{cc}
\ce{^{1°}CH3}\\
|\\
\ce{^{1°}CH3 - ^{3°}CH - ^{1°}CH3}
\end{array}\]

Primary C atoms = 3, Secondary C atoms = 0, Tertiary C atoms = 1