Question

How many tertiary carbon atoms and primary carbon atoms respectively are present in 2-iodo-3, 3- dimethyl pentane?

Options

• 0, 4

• 2, 3

• 1, 3

• 2, 4

Answer 1

0, 4

Explanation:

\[\begin{array}{cc}
\phantom{..}\ce{^{1°}CH3}\\
\phantom{.}|\\
\ce{H3^{1°}C - ^{2°}CH - ^{4°}C - ^{2°} CH2 - ^{1°} CH3}\\
|\phantom{........}|\phantom{........}\\
\ce{I}\phantom{......}\ce{^{1°}CH3}\phantom{.....}
\end{array}\]

No. of 3° carbon atoms = 0

No. of 1° carbon atoms = 4.