Question

How many three-digit positive integers exist that when divided by 6 leave a reminder of 4?

Options

• 149

• 150

• 151

• 152

Answer 1

The numbers which satisfy the property are 100,106,112,.......,994 which forms an A.P with the first term as 100, common difference 6and last term as 994.
Let the number of terms be n.
Hence 994 =100 +(n - 1) x 6
⇒ 894 = ( n - 1) x 6
⇒ (n - 1) = 149
⇒n = 150.
Hence option 150 is the correct option.