Advertisements
Advertisements
Question
Identify the anion present in the following compounds.
The solution of Compound L on reacting with freshly prepared ferrous sulphate solution followed by the addition of a few drops of concentrated sulphuric acid to the reactants along the sides of a test tube forms a brown ring at the junction of the two liquids.
Solution
Nitrate ion `("NO"_3^-)`
Explanation:
The formation of the brown ring at the junction of the two liquids indicates the brown ring test which is generally performed to test the presence of nitrate ion `("NO"_3^-)`. Hence the compound L must contain the nitrate ion in order to give brown ring on reacting with ferrous sulphate followed by the addition of sulphuric acid along the sides of the test tube.
APPEARS IN
RELATED QUESTIONS
The compound that will produce sulphur dioxide gas when reacted with dilute HCl.
The solution of this compound produces dirty green precipitate with NaOH.
A student takes Cu, Al, Fe and Zn strips, separately in four test tubes labeled as I, II, III and IV respectively. He adds 10 ml of freshly prepared ferrous sulphate solution to each test tube and observes the colour of the metal residue in each case.
He would observe a black residue in the test tubes:
