Question

Identify the products A and B in the following reaction.

\[\ce{Ethylpropanoate ->[(i) LiAlH4][(ii) H3O^+] A + B}\]

Options

• A = Butanoic acid, B = Methanoic acid

• A = Propanoic acid, B = Ethanal

• A = Propanal, B = Ethanoic acid

• A = Propan-1-ol, B = Ethanol

Answer 1

A = Propan-1-ol, B = Ethanol

Explanation:

\[\begin{array}{cc}\\
\ce{O}\phantom{.....................................................}\\
||\phantom{.....................................................}\\
\ce{\underset{Ethylpropanoate}{H3C - CH2 - C - O - CH2 - CH3} + LiAlH4 ->[{4[H]}] \underset{Propan-1-ol}{H3C - CH2CH2OH} + \underset{Ethanol}{CH2CH2OH}}
\end{array}\]