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Question
If `sqrt2` = 1.414, and the square_root() function returns -1.414, does it violate the following specification?
-- square_root (x)
-- inputs: x is a real number , x ≥ 0
-- outputs: y is a real number such that y2 = x
One Line Answer
Solution
No, because (- 1.414)2 = 2, which satisfies input – output relation (y2 = x)
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RELATED QUESTIONS
When do you say that a problem is algorithmic in nature?
Suppose you want to solve the quadratic equation ax2 + bx + c = 0 by an algorithm.
quadratic_solve (a, b, c)
-- inputs:?
-- outputs:?
You intend to use the formula and you are prepared to handle only real number roots. Write a suitable specification.
x = `(-b ± sqrt(b^2) - 4ac)/(2a)`
