Question

If 2 moles of an ideal gas at 546 K has volume of 44.8 L, then what will be it's pressure? (R = 0.082)

Options

• 3.129 atm

• 2.408 atm

• 1.098 atm

• 1.998 atm

Answer 1

1.998 atm

Explanation:

P₁ = 1 bar,    V₁ = 2.27 L

P₂ = 0.227 bar, V₂ = ?

According to Boyle's Law,

∴ `"V"_2 = ("P"_1"V"_1)/"P"_2 = (1 xx 2.27)/0.227` = 10 L

∴ The rise in volume of gas = 10 - 2.27 = 7.73 L