Question

If, 2 moles of an ideal gas at 546 K has volume of 44.8 L, then what will be it's pressure?

Options

• 3.129 atm

• 1.098 atm

• 1.998 atm

• 2.408 atm

Answer 1

1.998 atm

Explanation:

Given,

n = 2 mol, T = 546 K, V = 44.8 L, R = 0.082 L atm mol^-1K^-1

According to ideal gas equation,

pV = nRT

⇒ p = `"nRT"/"V"`

`= (2 "mol" xx 0.082 "L atm mol"^-1 "K"^-1 xx 546 "K")/(44.8 "L")`

`= 89.544/44.8` atm

= 1.998 atm