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Question
If α + β = 4 and α3 + β3 = 44, then α, β are the roots of the equation:
Options
2x2 – 7x – 7 = 0
3x2 + 8x + 12 = 0
3x2 – 12x + 5 = 0
none of these
MCQ
Solution
3x2 – 12x + 5 = 0
Explanation:
α3 + β3 = (α + β)3 – 3αβ(α + β)
⇒ 44 = (4)3 – 3αβ × 4
⇒ 44 – 64 = – 12 αβ
⇒ αβ = `20/12 = 5/3`
∴ quadratic equation is
x2 – (α + β)x + αβ = 0
⇒ x2 – 4x + 53 = 0
⇒ 3x2 – 12x + 5 = 0
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