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If 4 tanβ = 3, then 4sinβ-3cosβ4sinβ+3cosβ= ______. -

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Question

If 4 tanβ = 3, then `(4sinbeta-3cosbeta)/(4sinbeta+3cosbeta)=` ______.

Options

  • 0

  • `1/3`

  • `2/3`

  • `3/4`

MCQ
Fill in the Blanks

Solution

If 4 tanβ = 3, then `(4sinbeta-3cosbeta)/(4sinbeta+3cosbeta)=` ______.

Explanation:-

Dividing both numerator and denominator by cosβ,

`(4sinbeta-3cosbeta)/(4sinbeta+3cosbeta)=(4tanbeta-3)/(4tanbeta+3)=(3-3)/(3+3)=0`

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