Question

If `|(6i, -3i, 1),(4, 3i, -1),(20, 3, i)|` = x + iy, then ______.

Options

• x = 3, y = 1

• x = 1, y = 1

• x = 0, y = 3

• x = 0, y = 0

Answer 1

If `|(6i, -3i, 1),(4, 3i, -1),(20, 3, i)|` = x + iy, then x = 0, y = 0.

Explanation:

Given, `|(6i, -3i, 1),(4, 3i, -1),(20, 3, i)|` = x + iy

`\implies -3i|(6i, 1, 1),(4, -1, -1),(20, i, i)|` = x + iy

`\implies` x + iy = 0  ...[∵ C₂ and C₃ are identical]

∴ x = 0, y = 0