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Question
If A(2, 0) and B(0, 3) are two points, find the equation of the locus of point P such that AP = 2BP.
Solution
Let P(x, y) be a point on the required locus.
Then AP = 2BP, where A(2, 0) and B(0, 3)
∴ `sqrt((x - 2)^2 + (y - 0)^2) = 2sqrt((x - 0)^2 + (y - 3)^2`
On squaring both sides, we get,
(x – 2)2 + y2 = 4[x2 + (y – 3)2]
∴ x2 – 4x + 4 + y2 = 4(x2 + y2 – 6y + 9)
∴ x2 – 4x + 4 + y2 = 4x2 + 4y2 – 24y + 36
∴ 3x2 + 3y2 + 4x – 24y + 32 = 0
This is the required equation of the locus.
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