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Question
If `a + pi/2 < 2tan^-1x + 3cot^-1x < b`, then a and b are respectively.
Options
`pi/2` and 2π
`pi/2` and `-pi/2`
0 and π
0 and 2π
MCQ
Solution
`underline(pi/2 "and" 2π)`
Explanation:
`a + pi/2 < 2tan^-1x + 3cot^-1x < b`
⇒ `a + pi/2<2(tan^-1x + cot^-1x) + cot^-1x < b`
⇒ `a + pi/2 < pi + cot^-1x < b`
⇒ `a - pi/2< cot^-1x<b - pi`
As 0 < cot-1x < π,
a = `pi/2` and b = 2π
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Algebra of Functions
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