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Question
If A = (–7, 3], B = [2, 6] and C = [4, 9] then find B' ∩ C'
Solution
A = (–7, 3] = {x / x ∈ R, –7 < x ≤ 3}
B = [2, 6] = {x / x ∈ R, 2 ≤ x ≤ 6}
C = [4, 9] = {x / x ∈ R, 4 ≤ x ≤ 9}
B' = R – B
= R – {x / x ∈ R, 4 ≤ x ≤ 9}
= {x / x ∈ R, x < 2 or x > 6}
C' = R – C
= R – {x / x ∈ R, 4 ≤ x ≤ 9}
= {x / x ∈ R, x < 4 or x > 9}
∴ B' ∩ C' = {x / x ∈ R, x < 2 or x > 6} ∩ {x / x ∈ R, x < 4 or x > 9}
= {x / x ∈ R, x < 2 or x > 9}
= `(- ∞, 2) ∪ (9, ∞)`
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