Advertisements
Advertisements
Question
If A and B are foot of perpendicular drawn from point Q(a, b, c) to the planes yz and zx, then equation of plane through the points A, B and O is ______.
Options
`x/a + y/b - z/c` = 0
`x/a - y/b + z/c` = 0
`x/a - y/b - z/c` = 0
`x/a + y/b + z/c` = 0
Solution
If A and B are foot of perpendicular drawn from point Q(a, b, c) to the planes yz and zx, then equation of plane through the points A, B and O is `underlinebb(x/a + y/b - z/c = 0)`.
Explanation:
It is given that, the foot of perpendicular from point Q(a, b, c) to the yz plane is A(0, b, c) and the foot of perpendicular from point Q to the zx plane is B(a, 0, c).
Let the equation of plane passing through the point (0, 0, 0) be Ax + By + Cz = 0 ......(i)
As it is passing through the point A(0, b, c) and B(a, 0, c).
So, 0 + Bb + Cc = 0 and Aa + 0 + Cc = 0
`\implies` Cc = Bb and Cc = –Aa
Therefore, – Aa = – Bb = Cc = k
`\implies` A = `-k/a`, B = `-k/b` and C = `k/c`
`-k/ax - k/by + k/cz` = 0 ...[From equation (i)]
`\implies - x/a - y/b + z/c` = 0 or `x/a + y/b - z/c` = 0