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Question
If A and B are mutually exclusive events P(A) = `3/8` and P(B) = `1/8`, then find `"P"(bar"A" ∪ bar"B")`
Solution
`"P"(bar"A" ∪ bar"B") = "P"(bar("A" ∪ "B"))`
= 1 – P(A ∩ B)
Since A and B are mutually exclusive we have A ∩ B = Φ
∴ P(A ∩ B) = 0
`"P"(bar"A" ∪ bar"B")` = 1 – 0 = 1
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