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Question
If `overlinea`, `overlineb` and `overlinec` are three non-coplanar vectors then `(overlinea + overlineb + overlinec).[(overlinea + overlineb) xx (overlinea + overlinec)]` = ______
Options
0
`[overlinea overlineb overlinec]`
`-[overlinea overlineb overlinec]`
2`[overlinea overlineb overlinec]`
Solution
`-[overlinea overlineb overlinec]`
Explanation:
`[overlinea + overlineb + overlinec].[(overlinea + overlineb) xx (overlinea + overlinec)]`
= `(overlinea + overlineb).[(overlinea + overlineb) xx (overlinea + overlinec)] + overlinec.[(overlinea + overlineb) xx (overlinea + overlinec)]`
= 0 + `[overlinec overlinea + overlineb overlinea + overlinec]`
= `[overlinec overlinea overlinea + overlinec] + [overlinec overlineb overlinea + overlinec]`
= `[overlinec overlinea overlinea] + [overlinec overlinea overlinec] + [overlinec overlineb overlinea] + [overlinec overlineb overlinec]`
= `0 + 0 + [overlinec overlineb overlinea] + 0 = -[overlinea overlineb overlinec]`