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Question
If a, b, c are non-zeros, then the system of equations (α + a)x + αy + αz = 0, αx + (α + b)y + αz = 0, αx+ αy + (α + c)z = 0 has a non-trivial solution if
Options
α–1 = – (a–1 + b–1 + c–1)
α–1 = a + b + c
α + a + b + c = 1
None of these
MCQ
Solution
α–1 = – (a–1 + b–1 + c–1)
Explanation:
Given system of equation AX = O
Where A = `[(alpha + a, alpha, alpha),(alpha, alpha + b, alpha),(alpha, alpha, alpha + c)] x X = [(x),(y),(z)], O = [(0),(0),(0)]`
For non-trival solution,
D = 0
`|(alpha +a, alpha, alpha),(alpha, alpha + b, alpha),(alpha, alpha, alpha + c)|` = 0
`R_1 -> R_1 - R_2, R_2 -> R_2 - R_3`
⇒ `|(a, -b, 0),(0, b, -c),(alpha, alpha, alpha + c)|` = 0
⇒ abα + abc + acα + bcα = 0
⇒ abc = – α(ab + bc + ca)
⇒ `1/alpha = -(1/c + 1/a + 1/b)`
α–1 = – (a–1 + b–1 + c–1)
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