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If A = iiii[1+2ii-i1-2i], where i = -1, then A(adj A) = ______. -

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Question

If A = `[(1 + 2"i", "i"),(- "i", 1 - 2"i")]`, where i = `sqrt-1`, then A(adj A) = ______.

Options

  • - 2 l

  • 2 l

  • 5 l

  • 4 l

MCQ
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Solution

If A = `[(1 + 2"i", "i"),(- "i", 1 - 2"i")]`, where i = `sqrt-1`, then A(adj A) = 4 l.

Explanation:

We have , A = `[(1 + 2"i", "i"),(- "i", 1 - 2"i")]`

∴ |A| = `|(1 + 2"i", "i"),(- "i", 1 - 2"i")|`

= (1 + 2i)(1 - 2i) + i2

= 1 - (2i)2 + (- 1)

= 1 + 4 - 1 = 4

∴ A(adj A) = |A| l = 4 l

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