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Question
If A is non-singular matrix such that (A - 2l)(A - 4l) = 0 then A + 8A-1 = ______.
Options
l
0
3l
6l
MCQ
Fill in the Blanks
Solution
If A is non-singular matrix such that (A - 2l)(A - 4l) = 0 then A + 8A-1 = 6l.
Explanation:
We have, IAI ≠ 0
⇒ A-1 is exists.
Since, (A - 2l) (A - 4l) = 0
⇒ A2 - A(4l) - 2l( ) + Bl · l = 0
⇒ A2 - 4AI - 2Al + 8l = 0
⇒ A2 - 6Al + 8l = 0
⇒ A2 - 6A + 8l = 0
On pre multiply both sides by A-1, we get
A-1A2 - 6A-1 A + aA-1l= 0
⇒ lA - 6l + 8A-1 = 0
⇒ A - 6l + 8A-1 = 0
⇒ A + 8A-1 = 6l
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