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Question
If a linear equation has solutions (–2, 2), (0, 0) and (2, –2), then it is of the form ______.
Options
y – x = 0
x + y = 0
–2x + y = 0
–x + 2y = 0
Solution
If a linear equation has solutions (–2, 2), (0, 0) and (2, –2), then it is of the form x + y = 0.
Explanation:
Let us consider a linear equation ax + by + c = 0 ...(i)
Since, (–2, 2), (0, 0) and (2, –2) are the solutions of linear equation therefore it satisfies the equation (i), we get
At point (–2, 2), –2a + 2b + c = 0 ...(ii)
At point (0, 0), 0 + 0 + c = 0 ⇒ c = 0 ...(iii)
And at point (2, –2), 2a – 2b + c = 0 ...(iv)
From equations (ii) and (iii),
c = 0 and –2a + 2b + 0 = 0,
–2a = –2b,
`a = (2b)/2`
⇒ a = b
On putting a = b and c = 0 in equation (i),
bx + by + 0 = 0
⇒ bx + by = 0
⇒ –b(x + y) = 0
⇒ x + y = 0, b ≠ 0
Hence, x + y = 0 is the required form of the linear equation.
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