Question

If a pendulum which gives correct time beats second on ground at a certain place is moved to the top of a tower 320 m high, then the loss of time of the pendulum clock in one day, in second, is ______.

Options

• 2.16s

• 1.08 s

• 0.54 s

• 8.64 s

Answer 1

If a pendulum which gives correct time beats second on ground at a certain place is moved to the top of a tower 320 m high, then the loss of time of the pendulum clock in one day, in second, is 8.64 s. 

Explanation:

` "T" alpha sqrt(1/"g") alpha "R"`    `(therefore "g" = "GM"/"R"^2)`

` "T" alpha sqrt(1/"g") alpha  ("R" + "h") => "T"_1/"T" = ("R" +"H")/"R"` or

`("T"_1 - "T")/"T" = "T" xx "h"/"R" = (2 xx 320) / (6.4 xx 10^6) = 10^-4`s 

Loss of time in one day = `10^-4 xx 86400`

= 8.64 s