Question

If a spring extends by x on loading, then energy stored by the spring is (T is the tension in the spring and k is the spring constant)

Options

• T²/2x

• T²/2k

• 2k/T²

• 2T²/k

Answer 1

T²/2k

Explanation:

Extension of spring = x

Tension on spring = T

Spring constant = k

T = kx or x = `T/k`

∴ E = `1/2 xx kx^2`

= `1/2 xx k xx (T/k)^2 = T^2/(2k)`