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If abcandabcthenabcabc≠0 and|1+a1111+b1111+c|=0,then 1a+1b+1c= ____________. -

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Question

If `"abc" ne 0  "and" abs ((1 + "a", 1, 1),(1, 1 + "b", 1),(1,1,1 + "c")) = 0, "then"  1/"a" + 1/"b" + 1/"c" =` ____________.

Options

  • 1

  • 2

  • -1

  • -3

MCQ

Solution

If `"abc" ne 0  "and" abs ((1 + "a", 1, 1),(1, 1 + "b", 1),(1,1,1 + "c")) = 0, "then"  1/"a" + 1/"b" + 1/"c" =` -1.

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