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Question
If ABCD is a cyclic quadrilateral, then cos A + cos B + cos C + cos D = ______.
Options
0
1
2(cos B + cos D)
2(cos A + cos C)
MCQ
Fill in the Blanks
Solution
If ABCD is a cyclic quadrilateral, then cos A + cos B + cos C + cos D = 0.
Explanation:
Since, ABCD is a cyclic quadrilateral.
∴ A + C = 180°
⇒ A = 180° – C
⇒ cos A = cos (180° – C) = – cos C
⇒ cos A + cos C = 0 ......(i)
Also, B + D = 180°
⇒ cos B + cos D = 0 .....(ii)
Adding (i) and (ii), we get
cos A + cos B + cos C + cos D = 0
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Trigonometric Functions of Sum and Difference of Angles
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