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Question
If ABCD is a cyclic quadrilateral, then the value of cos A – cos B + cos C – cos D is equal to ______.
Options
0
1
2(cos B – cos D)
2(cos A – cos C)
MCQ
Fill in the Blanks
Solution
If ABCD is a cyclic quadrilateral, then the value of cos A – cos B + cos C – cos D is equal to 0.
Explanation:
We know that, A + C = 180°
Since ABCD is a cyclic quadrilateral.
`\implies` A = 180° – C
`\implies` cos A = cos(180° – C) = – cos C
`\implies` cos A + cos C = 0 ...(i)
Now, B + D = 180°, then
cos B + cos D = 0 ...(ii)
Subtracting equation (ii) from equation (i), we get
cos A – cos B + cos C – cos D = 0
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Trigonometric Functions of Sum and Difference of Angles
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