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Question
If the angle of elevation of cloud from a point 200 m above a lake is 30º and the angle of depression of its reflection in the lake is 60º, then find the height of the cloud above the lake
Sum
Solution
Let C be the cloud and C’ be its reflection in the lake.
Let CS = C’S = x.
`\text{Now, }\frac{BC}{AB}=\text{tan }30^\text{o}=\frac{1}{\sqrt{3}}`
`\Rightarrow x-200=\frac{AB}{\sqrt{3}}`
`\text{Also, }\frac{BC'}{AB}=\text{tan }60^\text{o}=\sqrt{3}`
`\Rightarrow x+200=(AB)\sqrt{3}.`
`\therefore \sqrt{3}(x-200)=\frac{x+200}{\sqrt{3}}\text{ or }x=\text{400}.`
∴ CS = 400 m.
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