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Question
If the angular speed of the earth is 7.26 x 10–5 rad/s and radius of the earth is 6,400 km,
calculate the change in weight of 1 kg of mass taken from equator to pole.
Sum
Solution
Given: R = 6.4 x 106 m, ω = 7.26 x 10–5 rad/s
To find: Change in weight (ΔW)
formulae:
`Deltag=g_p-g_(eq)=Romega^2`
`Delta W=mDeltag`
Calculation: From formula (i) and (ii),
ΔW = m(Rω2)
=`1xx6.4xx10^6xx(7.26xx10^-5)^2`
=`3373xx10^-5 N`
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