Question

If concentration of reactant 'A' is increased by 10 times the rate of reaction becomes 100 times. What is the order of reaction, if rate law is, rate = k[A]^x?

Options

• 3

• 2

• 4

• 1

Answer 1

2

Explanation:

Given, Rate_old = k[A]^x ................(i)

If the concentration of reactant 'A' is 10 times higher, then

Rate_new = k[10 A]^x

The rate of reaction increases by a factor of 100.

100 × rate_old = k[10 A]^x ...........(ii)

From Eq. (i) and (ii),

100 × k(A]^x = k[10 A]^x

100 = 10^x

10² = 10^x

x = 2