Question

If E, M and P are the kinetic energy, mass and linear momentum of a particle respectively, which of the following relations represents the angular momentum L of the particle when the particle rotates in a circle of radius R?

Options

• L² = 2MR

• L=`sqrt(2"ME")`

• L² = 2MR²E

• L = P²ME

Answer 1

`underline("L"^2 = 2"MR"^2 "E")`

Explanation:

K.E. of particle is,

`"E" = 1/2 "Mv"^2`

Linear momentum,

P = Mv

`therefore "P" = sqrt(2"ME")`

Angular momentum is given by,

L = P x R = `sqrt(2"ME")` x R

`therefore "L"^2 = 2"MER"^2`