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Question
If f(x) = `{(8-6x; 0<x≤2), (4x-12; 2<x≤3),(2x+10; 3<x≤6):}` then f(x) is ______
Options
continuous at x = 2 and discontinuous at x = 3
continuous at x = 3 and discontinuous at x = 2
continuous at x = 2 and x = 3
discontinuous at x = 2 and x = 3
MCQ
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Solution
`{(8-6x; 0<x≤2), (4x-12; 2<x≤3),(2x+10; 3<x≤6):}` then f(x) is continuous at x = 2 and discontinuous at x = 3.
Explanation:
`lim_{x→2^-} f(x) = lim_{x→2^-} (8 - 6x) = 8 - 12 = -4`
`lim_{x→2^+} f(x) = lim_{x→2^+} (4x - 12) = 8 - 12 = -4`
f(2) = 8 - 6(2) = -4
`lim_{x→3^-} f(x) = lim_{x→3^-}(4x - 12) = 12 - 12 = 0`
`lim_{x→3^+} f(x) = lim_{x→3^+} (2x + 10) = 6 + 10 = 16`
∴ `lim_{x→3^-} f(x) ≠ lim_{x→3^+} f(x)`
∴ f(x) is continuous at x = 2 and discontinuous at x = 3.
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Continuous and Discontinuous Functions
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