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Question
If `f(x) = log [e^x ((3 - x)/(3 + x))^(1/3)]`, then `f^'(1)` is equal to
Options
`3/4`
`2/3`
`1/3`
`1/2`
MCQ
Solution
`3/4`
Explanation:
`f(x) = log [e^x ((3 - x)/(3 + x))^(1/3)]`
= `x + 1/3 [log(3 - x) - log(3 + x)`
`f^'(x) = (7 - x^2)/(9 - x^2)`
`f^'(1) = (7 - 1)/(9 - 1) = 6/8 = 3/4`
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