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Question
If `"f" ("x") = sqrt (1 + "cos"^2 ("x"^2)), "then the value of f'" (sqrtpi/2)` is ____________.
Options
`sqrtpi/6`
`-sqrt(pi/6)`
`1/sqrt6`
`pi/sqrt6`
MCQ
Fill in the Blanks
Solution
If `"f" ("x") = sqrt (1 + "cos"^2 ("x"^2)), "then the value of f'" (sqrtpi/2)` is `underline(-sqrt(pi/6))`.
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