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Question
If Load = 48 kgf and efficiency is 80% then calculate:
- Mechanical Advantage.
- Effort needed to lift the load.
Solution
Here, load, L = 48 kgf
Efficiency = 80% = 0.8
1. `η = ("M.A")/("V.R")`
M.A. = η × V.R.
M.A. = 2 × 0.8
M.A. = 1.6
2. M.A =` "Load"/"Effort"`
Effort = `"Load"/"M.A"`
E = `48/1.6`
= 30 kgf
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