Advertisements
Advertisements
Question
If the mean of 5 observation x, x + 2, x + 4, x + 6and x + 8 , find the value of x.
Solution
Mean of given observations =` "sun of given observations"/"total number of observations"`
∴ 11 =`(x + (x+2)+(x+4)+(x+6)+(x+8))/5`
⇒ 55 = 5x + 20
⇒ 5x = 55 – 20
⇒ 5x = 35
⇒ x =`35/5`
⇒ x = 7
Hence, the value of x is 7.
APPEARS IN
RELATED QUESTIONS
Find the mean of the following data:-
x | 19 | 21 | 23 | 25 | 27 | 29 | 31 |
f | 13 | 15 | 16 | 18 | 16 | 15 | 13 |
The weekly observations on cost of living index in a certain city for the year 2004 - 2005 are given below. Compute the weekly cost of living index.
Cost of living Index | Number of Students |
1400 - 1500 | 5 |
1500 - 1600 | 10 |
1600 - 1700 | 20 |
1700 - 1800 | 9 |
1800 - 1900 | 6 |
1900 - 2000 | 2 |
The mean of the following frequency distribution is 62.8 and the sum of all the frequencies is 50. Compute the missing frequency f1 and f2.
Class | 0 - 20 | 20 - 40 | 40 - 60 | 60 - 80 | 80 - 100 | 100 - 120 |
Frequency | 5 | f1 | 10 | f2 | 7 | 8 |
The algebraic sum of the deviations of a frequency distribution from its mean is always ______.
Which of the following cannot be determined graphically?
If the mean of observation \[x_1 , x_2 , . . . . , x_n is x\] then the mean of x1 + a, x2 + a, ....., xn + a is
If the mean of the following distribution is 7.5, find the missing frequency ‘f’:
Variable : | 5 | 6 | 7 | 8 | 9 | 10 | 11 | 12 |
Frequency: | 20 | 17 | f | 10 | 8 | 6 | 7 | 6 |
The value of `sum_(i=1)^nx_i` is ______.
There is a grouped data distribution for which mean is to be found by step deviation method.
Class interval | Number of Frequency (fi) | Class mark (xi) | di = xi - a | `u_i=d_i/h` |
0 - 100 | 40 | 50 | -200 | D |
100 - 200 | 39 | 150 | B | E |
200 - 300 | 34 | 250 | 0 | 0 |
300 - 400 | 30 | 350 | 100 | 1 |
400 - 500 | 45 | 450 | C | F |
Total | `A=sumf_i=....` |
Find the value of A, B, C, D, E and F respectively.
The following table gives the marks scored by a set of students in an examination. Calculate the mean of the distribution by using the short cut method.
Marks | Number of Students (f) |
0 – 10 | 3 |
10 – 20 | 8 |
20 – 30 | 14 |
30 – 40 | 9 |
40 – 50 | 4 |
50 – 60 | 2 |