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Question
If n(A) = 20, n(B) = 28 and n(A ∪ B) = 36 then n(A ∩ B) = ?
Sum
Solution
We have,
n(A) = 20, n(B) = 28 and n(A ∪ B) = 36
n(A ∪ B) = n(A) + n(B) - n(A ∩ B)
36 = 20 + 28 - n(A ∩ B)
36 = 48 - n(A ∩ B)
∴ n(A ∩ B) = 48 - 36
∴ n(A ∩ B ) = 12
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Number of Elements in a Set
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