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If nPr = 840, nCr = 35, then r = ______. - Mathematics

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Question

If nPr = 840, nCr = 35, then r = ______.

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Solution

If nPr = 840, nCr = 35, then r = 4.

Explanation:

Given that nPr = 840 and nCr = 35

⇒ `(n!)/((n - r)!)` = 840  .....(i)

And `(n!)/(r!(n - r)!)` = 35  ....(ii)

Dividing equation (i) by equation (ii) we get

`((n!)/((n - r)!))/((n!)/(r!(n - r)!)) =840/35`

⇒ `(n!)/((n - r)!) xx (r!(n - r)!)/(n!)` = 24

⇒ r! = 24

⇒ r! = 4 × 3 × 2 × 1

⇒ r! = 4!

∴ r = 4

Hence the value of the filler is 4.

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Derivation of Formulae and Their Connections
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Chapter 7: Permutations and Combinations - Exercise [Page 125]

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NCERT Exemplar Mathematics [English] Class 11
Chapter 7 Permutations and Combinations
Exercise | Q 41 | Page 125
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