Question

If one mole electrons is passed through the solutions of CrCl₃, AgNO₃ and NiSO₄, in what ratio Cr, Ag and Ni will be deposited at the electrodes?

Options

• 3 : 2 : 1

• 1 : 2 : 3

• 2 : 6 : 3

• 3 : 6 : 2

Answer 1

2 : 6 : 3

Explanation:

\[\ce{Cr^{3+} + 3e^- -> Cr}\]

\[\ce{Ag^+ + e^- -> Ag}\]

\[\ce{Ni^{2+} + 2e^- -> Ni}\]

If one mole of electron is passed, then the ratio of mass of Cr, Ag, Ni deposited will be

`1/3 : 1/1 : 1/2` = 2 : 6 : 3