Question

If one root of equation (p – 3) x² + x + p = 0 is 2, the value of p is ______.

Options

• – 2

• 2

• ± 2

• 1 and 2

Answer 1

If one root of equation (p – 3) x² + x + p = 0 is 2, the value of p is 2.

Explanation:

Given equation be

(p – 3) x² + x + p = 0   ...(1)

Since x = 2 is one root of equation (1)

∴ 2 satisfies the given equation (i).

`\implies` (p – 3) · 2² + 2 + p = 0

`\implies` 4(p – 3) + 2 + p = 0

`\implies` 4p – 12 + 2 + p = 0

`\implies` 5p – 10 = 0

`\implies` 5p = 10

`\implies` p = 2