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Question
If P1 and P2 are the lengths of the perpendiculars from the points (2, 3, 4) and (1, 1, 4) respectively from the plane 3x – 6y + 2z + 11 = 0, then P1 and P2 are the roots of the equation ______.
Options
P2 – 23P + 7 = 0
7P2 – 23P + 16 = 0
P2 – 17P + 16 = 0
P2 – 16P + 7 = 0
MCQ
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Solution
If P1 and P2 are the lengths of the perpendiculars from the points (2, 3, 4) and (1, 1, 4) respectively from the plane 3x – 6y + 2z + 11 = 0, then P1 and P2 are the roots of the equation 7P2 – 23P + 16 = 0.
Explanation:
P1 = `|(3(2) - 6(3) + 2(4) + 11)/(sqrt(3^2 + (-6)^2 + (2)^2))|` = 1
P2 = `|(3(1) - 6(1) + 2(4) + 11)/(sqrt(3^2 + (-6)^2 + (2)^2))| = 16/7`
The equation P1 and P2 satisfies 7P2 – 23P + 16 = 0.
∴ P1 and P2 P1 and P2 are the roots of the equation (B).
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Three Dimensional (3-D) Coordinate System
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