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Question
If six students, including two particular students A and B, stand in a row, then the probability that A and B are separated with one student in between them is ______.
Options
`8/15`
`4/15`
`2/15`
`1/15`
Solution
If six students, including two particular students A and B, stand in a row, then the probability that A and B are separated with one student in between them is `underlinebb(4/15)`.
Explanation:
Consider a group of three students A, B and another student in between A and B. Choice for a student between A and B is 4. A and B can interchange their places in the group in 2 ways.
Now the group of three students (student A, student B and a student in betWeen A and B) and the remaining 3 students can stand in a row in 4! ways.
Hence total number of ways to stand in a row such that A and B are separated with one student in between them = 4 × 2 × 4!
Now total number of ways to stand is 6 students stand in a row without any restriction = 6!
Hence required probability
= `(4 xx 2 xx 4!)/(6!)`
= `(4 xx 2)/(6 xx 5)`
= `4/15`